Stat

Assessment 3 – Hypothesis, Effect Size, Power, and t TestsComplete the following problems within this Word document. Do not submit other files. Show your work for problem sets that require calculations. Ensure that your answer to each problem is clearly visible. You may want to highlight your answer or use a different type color to set it apart.Hypothesis, Effect Size, and PowerProblem Set 3.1: Sampling Distribution of the Mean ExerciseCriterion: Interpret population mean and variance.Instructions: Read the information below and answer the questions.Suppose a researcher wants to learn more about the mean attention span of individuals in some hypothetical population. The researcher cites that the attention span (the time in minutes attending to some task) in this population is normally distributed with the following characteristics: 20 36 . Based on the parameters given in this example, answer the following questions:1. What is the population mean (μ)? __________________________2. What is the population variance ?  __________________________3. Sketch the distribution of this population. Make sure you draw the shape of the distribution and label the mean plus and minus three standard deviations.Problem Set 3.2: Effect Size and PowerCriterion: Explain effect size and power.Instructions: Read each of the following three scenarios and answer the questions.Two researchers make a test concerning the effectiveness of a drug use treatment. Researcher A determines that the effect size in the population of males is d = 0.36; Researcher B determines that the effect size in the population of females is d = 0.20. All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________Two researchers make a test concerning the levels of marital satisfaction among military families. Researcher A collects a sample of 22 married couples (n = 22); Researcher B collects a sample of 40 married couples (n = 40). All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________Two researchers make a test concerning standardized exam performance among senior high school students in one of two local communities. Researcher A tests performance from the population in the northern community, where the standard deviation of test scores is 110 (); Researcher B tests performance from the population in the southern community, where the standard deviation of test scores is 60 (). All other things being equal, which researcher has more power to detect an effect? Explain. ______________________________________________________________________Problem Set 3.3: Hypothesis, Direction, and Population MeanCriterion: Explain the relationship between hypothesis, tests, and population mean.Instructions: Read the following and answer the questions.Directional versus nondirectional hypothesis testing. Cho and Abe (2013) provided a commentary on the appropriate use of one-tailed and two-tailed tests in behavioral research. In their discussion, they outlined the following hypothetical null and alternative hypotheses to test a research hypothesis that males self-disclose more than females:· H0: µmales − µfemales ≤ 0· H1: µmales − µfemales > 01. What type of test is set up with these hypotheses, a directional test or a nondirectional test? ____________________________________________________2. Do these hypotheses encompass all possibilities for the population mean? Explain. ____________________________________________________Problem Set 3.4: Hypothesis, Direction, and Population MeanCriterion: Explain decisions for p values.The p-value summarizes the evidence provided by the sample against the null hypothesis. The p-value is the level of marginal significance within a statistical hypothesis test representing the probability of the occurrence of a given event. The p-value is used as an alternative to rejection points to provide the smallest level of significance at which the null hypothesis would be rejectedInstructions: Read the following and respond to the prompt.The value of a p value.In a critical commentary on the use of significance testing, Lambdin (2012) explained, “If a p < .05 result is ‘significant,’ then a p = .067 result is not ‘marginally significant’” (p. 76).Explain what the author is referring to in terms of the two decisions that a researcher can make.If the p-value is less than 0.05 then the computed statistic falls in the rejection region. Here we are comparing the p-value with the level of significance therefore, we reject the null hypothesis and conclude that based on the sample observations the hypothesis can be rejected.However, if the p-value is 0.67 then it is greater than 0.05 so the computed statistic falls in the acceptance region and we conclude that the sample data does not provide any evidence against the null hypothesis.t TestsProblem Set 3.5: One-Sample t test in SPSSCriterion: Calculate a one-sample t test in SPSS.Data: Riverbend City online news advertises that it is read longer than the national news. The mean for national news is 8 hours per week. The following sample of the Riverbend City online news readers is: 5, 7, 6, 2, 4, 8, 5, 4, 18, 21, 8, 7, 4, 5, 6.Instructions: Complete the following:a. Enter the data from Problem Set 3.5 into SPSS and name the variable as Time.b. In the Toolbar, click Analyze, select Compare Means, and then select One-Sample t Test.c. Select Time, then click Arrow to send it over to the right side of the table. In the box labeled Test Value, enter 8.d. Click OK and copy and paste the output into the Word document.e. State the nondirectional hypothesis.f. State the critical t for a = .05 (two tails).g. Answer the following: Is the length of viewing for Riverbend City online news significantly different than the population mean? Explain.Problem Set 3.6: Confidence IntervalsCriterion: Calculate confidence intervals using SPSS.Data: Use the SPSS output from Problem Set 3.5 above.Instructions: Based on the SPSS output from Problem Set 3.5, including a test value (population mean) of 8, calculate the 95% confidence interval.Problem Set 3.7: Independent Samples t TestCriterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test.Data: Use the information from Problem Set 3.7.Instructions: Complete the following:a. Identify the IV and DV in the study. _____________________________________b. State the null hypothesis and the directional (one-tailed) alternative hypothesis. ___________________________________________________c. Can you reject the null hypothesis at α = .05? Explain why or why not. ___________________________________________________Problem Set 3.8: Independent t Test in SPSSCriterion: Calculate an independent samples t test in SPSS.Data: Dr. Z divides her clients with depression into 2 groups. She asks Group 1 not to watch or read any news for two weeks while in therapy and asks Group 2 to continue with therapy as normal. The groups scored the following on measure of depression:Depression Scores:Group 1: 34, 25, 4, 64, 14, 49, 54Group 2: 24, 78, 59, 68, 84, 79, 57Instructions: Complete the following steps:a. Open SPSS and create a New Dataset.b. Click the Variable View tab and type Groups in the Name column. Click on the gray box in the Values column. Value Labels window appears. Enter 1 in the Value area and enter No News in the Label area. Click Add. Now enter 2 in the Value area and enter Treatment Only in the Label area. Click Add. Click OK. The Variable View screen appears.c. In row two, enter Scores in the Name column.d. Click Data View.e. Enter the depression scores data (e.g., 1 under Groups and 34 under Scores; 2 under Groups and 24 under Scores).f. In the Toolbar, click Analyze, select Compare Means, and then select Independent-Samples t Test.g. Select Scores, then click Arrow to send it over to the Test Variable box.h. Select Groups and then click Arrow to send it over to the Grouping Variable box.i. Click Define Groups and enter 1 for Group 1 and enter 2 for Group 2. Click Continue.j. Click OK and then copy and paste the output to the Word document.Problem Set 3.9: Independent t Test using ExcelCriterion: Calculate an independent samples t test in Excel.Instructions: Complete the following steps:a. Open Excel.b. On an empty tab, enter the data from Problem Set 3.7. Use column A for group 1 and column B for Group 2. In Cell A1, enter 1. In cell B1, enter 2.c. Enter the data for each group below the label.d. Click Data Analysis, select t-Test: Two-Sample Assuming Equal Variances. Click OK.e. In Variable 1 Range enter $A$2:$A$8. (Or, click the graph icon at the right of the box and highlight your data for Group 1. Then, click the graph icon.)f. In Variable 2 Range enter $B$2:$B$8.g. Then click OK. Your results will appear on a new tab to the left.h. Return to your data. Click Data Analysis, select t-Test: Two-Sample Assuming Unequal Variances. Then click OK.i. In Variable 1 Range enter $A$2:$A$8. (Or, click the graph icon at the right of the box and highlight your data for Group 1. Then, click the graph icon.)j. In Variable 2 Range enter $B$2:$B$8.k. Then click OK. Your results will appear on a new tab to the left.l. Copy the results from both t tests below.

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